2014年1月29日 · What is the inverse of the function f(x) = ex−e−x 2 f (x) = e x − e − x 2? I tried replacing ex e x by a variable but I still can't get it.

2010年11月14日 · Inversion of xe−x x e − x is a problem with combinatorial structure, from which one can also invert xex x e x and derive most of the properties at the Wikipedia page. At least …

2015年5月2日 · How can I find the inverse function of f(x) =xx f (x) = x x? I cannot seem to find the inverse of this function, or any function in which there is both an x x in the exponent as well as …

2009年1月26日 · To find the inverse of a function, you can follow the steps of "switching" the input and output values. For example, in the function f (x) = 3+x+ (e^x), you can rewrite it as y = …

2015年11月4日 · If you replace a constant with an arbitrary variable, you might be complicating things more than you think. ex + 1 e x + 1 is not difficult to invert, but ex + x e x + x (as we've …

By definition, inverse functions have the other one’s domain and range. The function f(x) =ex f (x) = e x has a domain x ∈ R x ∈ R (all real numbers) and range of y> 0 y> 0 (all positive numbers).

2020年1月22日 · The answer for the inverse from the book is f−1(x) = 1 2ln(1+x x−1) f − 1 (x) = 1 2 l n (1 + x x − 1) So, I can’t seem to get the positive sign for x in the denominator.

The function is f(x) =ex + 2e2x f (x) = e x + 2 e 2 x So to find the inverse I went

2017年5月15日 · Multiply the numerator and denominator of the fraction by ex e x. That should leave you with less exponentials to deal with. Clear e2x e 2 x

I'm trying to compute the Fourier Transform of e−|x| e − | x | however I receive a different answer than wolfram alpha. Wolfram Alpha gets 2 π−−√ 1 1+ε2 2 π 1 1 + ε 2 and I get 2 1+ε2 2 1 + ε …