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How do you calculate the pH of HCl? + Example - Socratic
2014年7月9日 · To calculate the pH of HCl you need to know the concentration expressed in molarity (mol HCl/L solution). You will use the following equation to find the pH. pH = -log[H+] This means you take the negative log of the hydrogen ion concentration to find the pH. The hydrogen ion concentration is the same as the concentration of the acid because HCl is a strong acid and dissociates as follows: HCl ...
pH - Chemistry - Socratic
The pH scale was originated by Sorensen. He set 0 pH as the hydrogen ion concentration of a 1.0 molar solution of a strong monoprotic acid (like HCl). 14 on the pH scale uses its standard as the hydrogen ion concentration in a 1.0 molar concentration of a strong base (like NaOH). pH is actually a negative logarithmic scale.
What is the concentration of HCl if its pH is 3? - Socratic
2018年4月29日 · The #"pH"# of an aqueous solution is given by the equation, #"pH"=-log[H^+]# #[H^+]# is the hydrogen ion concentration in terms of molarity; The dissociation equation for hydrochloric acid is: #HCl(aq)->H^+(aq)+Cl^(-)(aq)# So, one mole of hydrochloric acid contains one mole of hydrogen ions. Therefore, the hydrogen ion concentration will be, #3 ...
What is the pH of a .001 M solution of HCl? - Socratic
2016年1月8日 · "pH" = 3 Hydrochloric acid, "HCl", is a strong acid, which means that it dissociates completely in aqueous solution to form hydronium ions, "H"_3"O"^(+), and chloride anions, "Cl"^(-), in a 1:1 mole ratio. This tells you that every mole of hydrochloric acid will dissociate to produce one mole of hydronium ions and one mole of chloride anions in aqueous solution. The balanced chemical equation ...
How to calculate pKa of HCl? - Socratic
2014年11月28日 · The ionisation of HCl can be shown as: HCl + H_2O -> H_3O^+ + Cl^- K_a can be calculated as the ratio of the product of the concentrations of the products to that of the reactant, that is, K_a= ([H_3O^+][Cl^-])/([HCl]) Since HCl is a strong acid, the value of K_a turns out to be very large, that is, K_a=10^7/1=10^7 (approx.) The value of pK_a is given by pK_a=-logK_a pK_a=-(log10^7) pK_a=-(7 ...
What is the pH of a .025 M HCl solution? - Socratic
2016年6月6日 · The pH is 1.60. > Hydrochloric acid is a strong acid that completely dissociates in water. For a 0.025 M HCl solution the concentration of the hydrogen ions, ["H"^+], is 0.025 moles/liter (i.e. 0.025 M). pH is defined as -log ["H"^+]. Substituting 0.025 into the equation for pH we find that the 0.025 M HCl solution has a pH of -log(0.025) = 1.60.
How to calculate the pH value of 0.0001 M #"HCl"# - Socratic
2016年9月5日 · "pH" = 4.0 Hydrochloric acid, "HCl", is a strong acid, which means that it dissociates completely in aqueous solution to produce hydronium cations, "H"_3"O"^(+), and chloride anions, "Cl"^(-). In order to calculate the pH of this solution, you need to know the concentration of hydronium cations.
What is the pH of a solution of concentrated HCl, the which …
2017年11月1日 · Well pH=-log_10[H_3O^+]=0.930 First we determine the concentration of our HCl solution.... "Concentration"="Moles of HCl"/"Volume of solution..." We start with a 10*mL volume whose mass is 10*mLxx1.19*g*mL^-1=11.9*g, and 36% of …
What is the pH of a 25 ml solution of 0.1 N HCl? - Socratic
2018年1月3日 · Normality for a substance is just the molarity that would be neutralized by the "H"^(+) from an incoming acid or "OH"^(-) from an incoming base that you could get if that substance dissociated completely. Since there is only one "H"^(+) in "HCl", "0.1 N HCl" = "0.1 M HCl". [If it was "0.1 M H"_2"SO"_4, then it would be "0.2 N H"_2"SO"_4, because "0.2 M" of "OH"^(-) is needed to neutralize "0.1 ...
pH calculations - Chemistry - Socratic
pH or potential of hydrogen is a scale of acidity from 0 to 14. It tells how acidic or alkaline a substance is. More acidic solutions have lower pH (less than 7). More alkaline solutions have higher pH (greater than 7). Substances which are not acidic or alkaline (neutral) usually have a pH of 7 (this is the answer to your question).