2011年1月8日 · Here is a Java version which is well suited for small N and very large target sum, when complexity O(t*N) (the dynamic solution) is greater than the exponential algorithm. My version uses a meet in the middle attack, along with a little bit shifting in order to reduce the complexity from the classic naive O(n*2^n) to O(2^(n/2)) .

2010年2月25日 · An algorithm is the description of an automated solution to a problem. What the algorithm does is precisely defined. The solution could or could not be the best possible one but you know from the start what kind of result you will get. You implement the algorithm using some programming language to get (a part of) a program.

2009年10月5日 · In an unstable sort algorithm, straw or spork may be interchanged, but in a stable one, they stay in the same relative positions (that is, since straw appears before spork in the input, it also appears before spork in the output). We could sort the list of words using this algorithm: stable sorting by column 5, then 4, then 3, then 2, then 1.

I have a series of questions in which I need feedback and answers. I will comment as to what I think, this is not a homework assignment but rather preparation for my exam. My main problem is determ...

2009年9月1日 · Stuff you know: A common way to classify algorithms is by runtime, and by citing the big-Oh complexity of an algorithm, you can get a pretty good estimation of which one is "better" -- whichever has the "smallest" function in the O! Even in the real world, O(N) is "better" than O(N²), barring silly things like super-massive constants and the like.

2016年6月13日 · The naive algorithm is O(n^2), and I assume what you actually mean is that you want something of lower order than that. As Maxim100 says, you can preserve the order by pairing the list with a series of numbers, use any algorithm you like, and then resort the remainder back into their original order.

2016年1月21日 · The same applies to the 14-bit integer PIN, so guessing the PIN would require you to solve a 2^14 possible outcome puzzle, hence an algorithm of time complexity O(2^n). So, those types of problems, where combinations of elements in a set S differs, and you will have to try to solve the problem by trying all possible combinations, will have this ...

2008年12月30日 · Keeping abstraction in mind, I've chosen not to implement the algorithm in a specific programming language but rather as pseudo-code. First I'll consider an algorithm to compute just 2 iterations of the spiral using 4 pairs of while loops. The structure of each pair is similar, yet distinct in its own right.

2010年5月24日 · D* Lite vs A*: The D* Lite algorithm works by basically running A* search in reverse starting from the goal and attempting to work back to the start. The solver then gives out the current solution and waits for some kind of change in the weights or obstacles that it …

SuperMemo algorithm. Here are some terms that we will deal with when impementing the SuperMemo (SM-2) algorithm of spaced repetition. repetitions - this is the number of times a user sees a flashcard. 0 means they haven't studied it yet, 1 means it is their first time, and so on. It is also referred to as n in some of the documentation.